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本帖最後由 tommywgt 於 2009-11-5 05:41 PM 編輯 % [6 G d3 ~/ z9 t5 i0 Q$ ~& y- P- B
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因為無法回覆, 所以開新文回答....* X; [0 n' Z3 V4 ]
ABT={2'b00, DATA, 4'b0000};
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# f5 J" A. t6 r0 lVerilog 常用的operator, j/ \) R) _4 F0 Z9 V$ L
– Binary bit-wise operators: ~, &, |, ^, ~^, ^~
7 `5 v/ }# S3 M% A: i: V+ ]" P– Unary reduction operators: &, ~&, |, ~|, ^, ~^, ^~
- {, o" w8 f% w: p( Q! m" p3 D4 z– Logical operators: !, &&, ||
% @: U! X" W, J– 2’s complement operators: +, -, *, /, %, B3 A: x. y9 j; v8 s% }5 q
– Relational operators: >, <, >=, <=, ==, !=, ===, !==
- H8 k: G8 h/ \2 v) j2 q– Logical shift operators: >>, <<
) l* _: z5 e8 f– Conditional operators: ? :
# {* i* w; E# f+ U– Duplication operators: {n{ <exp> <,<exp>> *}}
3 K( [1 i3 h* A6 b6 r2 F– Concatenation operators: {}' e" D9 _" S( n5 q
給你參考一下 |
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