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[問題求助] 為何先做DC分析 才接著做AC分析

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1#
發表於 2016-12-1 01:26:55 | 只看該作者 回帖獎勵 |倒序瀏覽 |閱讀模式
這是小弟寫的文章 編講義用的 歡迎高手同行找碴:2 N' i, L  R) q1 L1 b( E  `
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This section highlights the importance of an accurate pre-determined DC compact model.\cite{dc!!!}
7 _9 Y# |% R& wFor compact model developers, extraction of the DC parameters always needs to be carried out before the extraction of AC ones.8 y: L3 P' i- c
For devices measurement, DC measurement has to be carried out before AC measurement.2 N3 k" M. q2 {: k5 S
For modern IC designers, DC analysis needs to be carried out before AC analysis.\cite[4.6.4]{smith!}
: r) C4 R& p- uFor SPICE-like simulators, DC simulation also needs to be swept first and then follows by AC simulation.\cite{nlz!}
5 F( n! F4 A& K' [% u/ rFrom the device-level perspectives,, m# ]# S% j9 V9 s3 q+ L, J* f$ j
a set of equations which describe the terminal characteristics of DUT are written in a compact model.
. K, N" g/ K& T$ Z6 m# v0 [/ uThe equations are solved by SPICE-like simulators.
  j8 A& R9 B, [1 c  x" rThe procedure of establishing equations, describing device's electrical characteristics, in a compact model
. {1 t; @& r3 u6 c" Tand have them solved by SPICE-like simulators is termed as: Device Characterization.  h9 T" |( P( h1 H! O3 q
The fully Characterizations are treated by two independent steps:& V3 C, s3 `- `$ s* f
(1)DC Characterization or DC parameters extraction
4 ]' n/ W9 z' y. x" P/ K(2)AC Characterization or AC parameters extraction
7 m& p, D, d: LCharacterizing a nonlinear electronics component always begins with
# T7 ^# M5 A8 N# Q9 V1 m6 {DC characterization and follows by the AC characterization.# @1 m4 c5 a9 b: u8 u/ V5 g
Because the AC model is origined from the linearization of the DC model at an indicated operating point.+ ]- D+ C1 X$ v# L2 }4 ]
Accordingly, accuracy is highly required in DC characterization because of its piority in the procedure of parameter extraction .& l+ ?- j0 X- K2 y3 H( X

: \$ O2 y3 u  x% k5 g! Z6 Y9 O- CFrom the circuit-level perspectives,,  k8 V8 h/ \% M0 ~5 j% t
Circuit analysis refers to solving a circuit with KVL and KCL.1 p* x: J( g% q$ X: E
To be more specific, it means solving out nodes voltages and branches currents of each element in a circuit.
+ T( D# K# U! _1 qAs the source of stimulus can be systematically separated into DC sources and AC sources,
4 U7 m% R9 ^4 i$ t' H, H. \the unknown/solutions of the circuit are also separated into DC part and AC part.
* a: s6 G* x- d- ^; OAnalyzing a circuit is treated in two independent meansA)DC analysis (B)AC analysis
+ C" l; n! k' H1 \3 q' Z9 U2 A! A. IThe separation between DC analysis and AC analysis greatly simplified a complex circuit., T: r9 z6 b  Q: T4 b, J; I
DC analysis is being carried out before AC analysis.
2 n! |: M0 h8 O+ MDC analysis determines the Q-point, including each node voltage and branch current.1 c) l- J8 t( A0 a* t8 S
AC analysis gives the frequency response, including bandwidth and gain.5 O3 [/ p* R8 n( Y
Before performing AC Analysis, the DC operating point needed to be calculated from DC analysis first.
; T7 B  G$ S# a9 gThis is to construct a linear small-signal model for the nonlinear component.% y4 ~9 W& X* ?' }. y
So, the small signal (AC) response is highly dependent upon the presetting (DC) bias condition .
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; o, C7 e' q' b. n& z/ IDC simulation in analog SPICE-like simulator, aims for computing the equilibrium points,
' j, u7 @' _0 ]/ ~which are the calculated DC node voltages and DC branch currents in a circuit.( s$ v( p. v2 o. s, s
They are the DC solutions of the DC equivalent equation/circuit.
+ s! a$ b' f9 x, \: ]$ SA circuit will only reach its equilibrium if its stimulus is off5 M! e% Z# ~% Q! L
and the independent sources are remain constantly employed.$ R: y! ]5 T3 ~

$ r" a5 }/ R' x* k
' f  Q3 p$ c& i4 tThere is an important reason why a given electronics circuit always
+ q$ ~1 P, H! Y' y5 Dneed to be reduced into a DC equivalent circuit (large-signal model)$ p5 }+ W+ q; R! Y. K
and followed by an AC equivalent one(small-signal model).3 x) z+ ]) D  b( Y8 ?3 \8 `
It has to do with the present of an active component in the circuit.
, Z# T0 p9 Z' u& sThe active component is a nonlinear element.So, it will have to be linearized.
: s+ E* `! p4 fThe employment of active elements, like transistors, make the circuit a nonlinear algebra system.
' p8 z2 U& e# G9 G3 @+ LNormally, the nonlinear equation can only be solved by means of iterative methods,
$ V! \- K3 Z, B& F. M# U* esuch as Newton-Raphson algorithm \cite{nlz!}. This algorithm transforms the solutions
- h+ c( L4 X4 R3 Bof the nonlinear equation into a sequence of linear equation.
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2#
 樓主| 發表於 2016-12-1 01:27:12 | 只看該作者
接著寫....
- H5 n3 @1 `) J  D: A, fLikely, in linear electronic circuits, the superposition principle skillful separates all the electrical characteristics, voltages and currents,, ^3 x' l$ P4 n- j! m, E& U" L5 b
into the DC part and the AC part. The AC signals are superimposed on the DC signals.* N0 A2 @) `8 b% E
The two independent quantities, AC quantities and DC quantities,) g1 f' u% a/ \6 [
can be determined by means of two independent means in circuit analyses.
% o) @5 v' l. NFirstly, DC analysis is carried out in order to determine DC bias points, which are the DC quantities $V_{E}$ $V_{B}$ $V_{C}$ $I_{E}$ $I_{B}$ $I_3 ~4 w# r- z5 b' x# r% h0 i
{C}$.The DC analysis are performed when the original circuit is simplified into the equivalent DC circuit. Where all the passive elements are, [8 f1 V! M, M2 d' m3 {
remained in the circuit, but all the reactive elements such as: capacitors and inductors are removed.
; X# M0 A* [1 q+ T- u: U% tSecondly, the AC analysis is performed on the equivalent AC circuit, which is the so called: the small-signal equivalent circuit." o$ D! W# g4 h& Q
The equivalent AC circuit is executed by removing all the DC sources and replacing transistors with the small-signal models.
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