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[問題求助] 為何先做DC分析 才接著做AC分析

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發表於 2016-12-1 01:26:55 | 只看該作者 回帖獎勵 |倒序瀏覽 |閱讀模式
這是小弟寫的文章 編講義用的 歡迎高手同行找碴:
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; T  q' k7 d) [/ h. V7 M* iThis section highlights the importance of an accurate pre-determined DC compact model.\cite{dc!!!}% u0 p- D3 p) K2 ~- s. p
For compact model developers, extraction of the DC parameters always needs to be carried out before the extraction of AC ones.
7 E' b1 j$ {; B/ ^& Y. `For devices measurement, DC measurement has to be carried out before AC measurement.
/ R) V# j( M4 {$ v% C2 E0 ^For modern IC designers, DC analysis needs to be carried out before AC analysis.\cite[4.6.4]{smith!}
4 k% a0 i. q( m2 l2 D; C% e' kFor SPICE-like simulators, DC simulation also needs to be swept first and then follows by AC simulation.\cite{nlz!}
$ M+ N: z# e# k) [0 G; ^From the device-level perspectives,5 ?5 C9 G  P. ?6 H
a set of equations which describe the terminal characteristics of DUT are written in a compact model.
: ?- P8 U) P$ ~* F, u4 SThe equations are solved by SPICE-like simulators.
, J' n2 ?, A& j3 L8 RThe procedure of establishing equations, describing device's electrical characteristics, in a compact model* p3 E9 f4 a. L# Q! s" F5 E5 L
and have them solved by SPICE-like simulators is termed as: Device Characterization.
/ u5 i" h' j1 H# q: l# Z% ^2 V: UThe fully Characterizations are treated by two independent steps:9 m" x( o+ c5 `. }- L
(1)DC Characterization or DC parameters extraction
; T; k4 L/ W" A0 h- u# _8 y  Q* ?: N(2)AC Characterization or AC parameters extraction! K; `4 X* K% H. i) J6 K
Characterizing a nonlinear electronics component always begins with
: I* r' v3 A: r( w( ZDC characterization and follows by the AC characterization.9 I4 s- J# r& F, @) y* o% u  k/ n
Because the AC model is origined from the linearization of the DC model at an indicated operating point.
" ^: J7 U6 p/ k7 m$ ~Accordingly, accuracy is highly required in DC characterization because of its piority in the procedure of parameter extraction .  `. B1 L2 [. i. B7 f6 }- `

# U7 Y" u- M9 ~& fFrom the circuit-level perspectives,,
! T& C' b; S5 J& o9 D$ K. |Circuit analysis refers to solving a circuit with KVL and KCL.  G+ e- I& m2 Y6 |1 c+ a
To be more specific, it means solving out nodes voltages and branches currents of each element in a circuit./ I+ A+ x. e% ~1 K9 S# I
As the source of stimulus can be systematically separated into DC sources and AC sources,; i- t+ q3 w7 f) S' p! \% j! l
the unknown/solutions of the circuit are also separated into DC part and AC part.3 p& V0 F6 ]: y3 P$ r
Analyzing a circuit is treated in two independent meansA)DC analysis (B)AC analysis! C  \+ l5 O+ [, j% U
The separation between DC analysis and AC analysis greatly simplified a complex circuit.
- T) |2 v3 Z, TDC analysis is being carried out before AC analysis.
5 }& F5 H  g% m4 kDC analysis determines the Q-point, including each node voltage and branch current.
8 s8 s5 u! ?  o) `AC analysis gives the frequency response, including bandwidth and gain.
5 I* S/ s: v! W7 M9 D+ C* z' MBefore performing AC Analysis, the DC operating point needed to be calculated from DC analysis first.) A  j/ W; v6 ~: P  a
This is to construct a linear small-signal model for the nonlinear component.! b  I9 g; ]6 B5 ~2 W
So, the small signal (AC) response is highly dependent upon the presetting (DC) bias condition .7 i9 z2 }" H% k" {. l

6 x$ f! N6 `8 |  RDC simulation in analog SPICE-like simulator, aims for computing the equilibrium points,
' m- A- Q3 m. b$ xwhich are the calculated DC node voltages and DC branch currents in a circuit.
2 W) N( \$ l1 p: O" S8 m. N9 @They are the DC solutions of the DC equivalent equation/circuit.7 ^7 K  ~4 B( t- d! h
A circuit will only reach its equilibrium if its stimulus is off$ N; }, q8 p6 K& |" ?: X
and the independent sources are remain constantly employed.
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6 a& F5 _2 v4 ^, Y, C3 ~+ `( ZThere is an important reason why a given electronics circuit always6 U& ]+ n1 u  ]# x! p9 I8 Y( J
need to be reduced into a DC equivalent circuit (large-signal model)! G0 M( k8 }/ D# O  Z$ `
and followed by an AC equivalent one(small-signal model).
# R; Q( y7 P2 A7 e$ ?) G) hIt has to do with the present of an active component in the circuit.. l: ?) g4 N$ @6 V! l& R
The active component is a nonlinear element.So, it will have to be linearized.8 t- o6 [, R- w4 z
The employment of active elements, like transistors, make the circuit a nonlinear algebra system.
) a' @8 w! Z+ z* \5 r$ HNormally, the nonlinear equation can only be solved by means of iterative methods,: B) l1 A$ Q  J  u' Y7 {
such as Newton-Raphson algorithm \cite{nlz!}. This algorithm transforms the solutions
7 h* O8 Z+ O; d, j0 Y  c2 V4 rof the nonlinear equation into a sequence of linear equation., t. u$ h- w" [: p$ h
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2#
 樓主| 發表於 2016-12-1 01:27:12 | 只看該作者
接著寫....! h2 C- u' Z! e1 T: ^
Likely, in linear electronic circuits, the superposition principle skillful separates all the electrical characteristics, voltages and currents,
+ f4 f  h, f7 b& {0 Cinto the DC part and the AC part. The AC signals are superimposed on the DC signals.1 F9 K8 E3 v! n% S- {* I' w& Y/ Q
The two independent quantities, AC quantities and DC quantities,+ [) B1 o2 ]$ x+ _- O3 Y2 |
can be determined by means of two independent means in circuit analyses.  h% e( H; u$ t& V8 M, C# `
Firstly, DC analysis is carried out in order to determine DC bias points, which are the DC quantities $V_{E}$ $V_{B}$ $V_{C}$ $I_{E}$ $I_{B}$ $I_" o! P. X% V; ]
{C}$.The DC analysis are performed when the original circuit is simplified into the equivalent DC circuit. Where all the passive elements are! K  ]; M. P% p1 d+ ]
remained in the circuit, but all the reactive elements such as: capacitors and inductors are removed.* Y6 v! [) O: f# v1 V2 g
Secondly, the AC analysis is performed on the equivalent AC circuit, which is the so called: the small-signal equivalent circuit.$ j! N8 M2 P  c1 G
The equivalent AC circuit is executed by removing all the DC sources and replacing transistors with the small-signal models.
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