Chip123 科技應用創新平台

 找回密碼
 申請會員

QQ登錄

只需一步,快速開始

Login

用FB帳號登入

搜索
1 2 3 4
查看: 3725|回復: 0
打印 上一主題 下一主題

[問題求助] 請教2題棘手的數位邏輯問題~謝謝~

  [複製鏈接]
跳轉到指定樓層
1#
發表於 2008-12-2 10:30:45 | 只看該作者 回帖獎勵 |倒序瀏覽 |閱讀模式
各位高手" I7 I* x1 F6 N0 o  T' C
最近遇到2題蠻難的數位邏輯問題8 L' U  X* u/ c
希望能po上來尋求解題    謝謝!!
9 k; v8 R4 E7 i* z/ n8 Q- c9 D# k4 J. f+ d/ v) c. f8 c
1. You are given two identical sequential networks which realize the state table shown.  One network is initially in state “a” and the other network is initially in state “c”.  Specify an input sequence which could be used to distinguish between the two networks, and show the corresponding output sequence for each network for your “distinguishing sequence”.  Show that the sequence you found is the shortest distinguishing sequence (what is the length).   You must solve this in a procedural manner.  Trial and error guessing will not be accepted.  $ u% w- E1 e: {  K' {" q5 G

7 Q1 i' o( \" }* pPresent. P( Y6 U' v1 T+ o) B
State           Next State for  x =
/ C6 L+ ^+ H# w; c5 h+ ]/ ], g, u                0            1
+ `4 X4 G0 i) ~ a             c , 0       f , 09 b6 I+ J* ~) m3 d# d/ [
b             d , 0       e , 0  & n1 d* ]' ]$ H& W% z2 Y
c             h , 0       g , 0+ i- ?! }& A6 ^% Y7 q
d             b , 0       g , 0
/ ?1 I* f, ?, q& o; R6 a# v  t e             e , 0       b , 1
) F3 T* v" W' }% j) \/ ?: }; q f             f , 0       a , 16 T+ e9 f0 i5 a2 \7 g' R
g             c , 0       g , 1
4 D- F) [6 F9 p# M4 S3 m5 n h             c , 0       f , 0
# n+ v2 I# L& A+ J+ Y5 ?/ e4 g8 c2 f# a6 n. y2 y/ ?3 z
. S; _! s8 Z0 P& f9 T  j( G6 v: T
2.This is a combinational problem.   You will need to investigate a technique known as Bridging.   This technique constructs the desired function F out of a chosen function F1.
! C5 E& M: _; Q' {0 CF = F1∙G1 + G2        where# e$ k! a8 D; @- ]. q& K1 r
G1  and G2 are chosen so as to “bridge” between F2 and F, and either G1 or G2 may also be Null.    (Hint:  this can be hard to find so you may want to look for material written by John Peatman.)
: B; v  Z& t& L, p2 O
6 o9 a& S/ o1 ^1 r% ]Use bridging to implement each of the 3 functions below.      
% A% L& X4 k. }3 N, r" F4 L
5 r% o1 r% h6 t) e) x! X  wFa(A,B,C,D)  =  ∑m(0,6, 9,10,15)
/ F2 v; ?8 r& C0 Q6 q2 n2 ?9 F# o$ T* x/ a! Q4 ^9 i# x
Fb(A,B,C,D)  =  ∑m(0,1, 4,5,6,9,10,15)
" K0 U" o$ X! C* i- g% f! A
& \; H7 \! C8 T* g, r" ~Fc(A,B,C,D)  =  ∑m(1,3,4,5,6, 9,10,12,15)" K: i2 s$ {- u! B$ y9 ^6 b) G

0 c- L# K5 G$ X+ ]! W& d' r+ [% b真的很難!   謝謝!!
分享到:  QQ好友和群QQ好友和群 QQ空間QQ空間 騰訊微博騰訊微博 騰訊朋友騰訊朋友
收藏收藏 分享分享 頂1 踩 分享分享
您需要登錄後才可以回帖 登錄 | 申請會員

本版積分規則

首頁|手機版|Chip123 科技應用創新平台 |新契機國際商機整合股份有限公司

GMT+8, 2024-4-27 10:31 AM , Processed in 0.104006 second(s), 18 queries .

Powered by Discuz! X3.2

© 2001-2013 Comsenz Inc.

快速回復 返回頂部 返回列表