Chip123 科技應用創新平台
標題:
有關音樂程式的頻率計算問題
[打印本頁]
作者:
p123315427
時間:
2011-6-18 10:20 PM
標題:
有關音樂程式的頻率計算問題
library IEEE;
( E6 n/ E+ n! E) f9 @$ g
use IEEE.STD_LOGIC_1164.ALL;
/ r7 W8 b9 T9 l* r1 c/ T% |
use IEEE.STD_LOGIC_ARITH.ALL;
! Y" Y2 J! K5 K
use IEEE.STD_LOGIC_UNSIGNED.ALL;
5 k8 k# D! S% o0 h
3 e9 L9 G ?7 L3 X1 D! t' i" v
---- Uncomment the following library declaration if instantiating
9 s# y; s: p7 D% l8 ~
---- any Xilinx primitives in this code.
8 P& r9 k8 O7 L4 h+ A
--library UNISIM;
% A' }8 p' h8 m/ ^2 L l
--use UNISIM.VComponents.all;
; R6 d8 {/ h/ c' N/ M& L- c W
entity musicmusic is
. s6 }) X" ?5 |1 M; Q; B z3 V! k
port( inclk : in std_logic; --Clock Signal
5 O3 i" n+ k+ y- H% L
spk : buffer std_logic; --speaker driver
) S3 N! W- p6 V; P S& }
reset :in std_logic;
6 V) E U) C: m; e5 T. s& A6 u
L1,L2 : in std_logic);
2 a1 g7 ]: I2 A$ k
end musicmusic ;
z" \! K2 d- Y4 {6 g$ J3 M$ b
--------------------------------------------------------------------------------------
. K$ F! t! g ]8 b$ v
architecture behave of musicmusic is
/ b4 \ X; I7 n, @3 L( F
signal tone : std_logic_vector(10 downto 0);
7 v' z6 d5 a; |* R0 c3 w
signal tone_count : std_logic_vector(10 downto 0);
L+ G/ R6 z8 q1 X
signal tone_index : integer range 0 to 19;
3 ]/ U( ^+ ^" ~* a
signal clk10_count : std_logic_vector(17 downto 0);
5 b8 D" B% S% ^8 E' m( F2 j) x7 {
--signal time : integer range 0 to 500;
7 Y8 T; S2 M- C, x
signal clk : std_logic;
$ r3 q( {. Z# p6 U! q4 s! a# j
signal clk10 : std_logic;
; X. [/ Q; u3 o" T0 `7 H
signal se1 : integer range 0 to 63;
8 k9 x* t( V* L* v9 ]# K$ x
signal se2 : integer range 0 to 160;
& G) j( w* D V8 E% X! G& O( w
signal se3 : integer range 0 to 35;
7 ] g+ }1 E; j& k2 }
-------------------------------------------------------------------------------------
; S0 f( G2 r, s
begin
5 n. O4 j+ v7 P- s1 \, @9 @: y
PROCESS(inclk) --generate 2Mhz clock signal
* O% b* d5 X5 d3 `8 N
variable cnt1 : INTEGER RANGE 0 TO 39;
. |9 `; Z8 V5 ~9 e
BEGIN
1 `6 k% U3 |& S1 u
IF inclk='1' AND inclk'event THEN
! w' r$ y0 T X, ?
IF cnt1=39 THEN cnt1:=0;
- k: ^3 m: o/ j; k* o
ELSE
% f( d( \$ L" \
IF cnt1<30 THEN clk<='1';
% ?4 }, G6 r- P
ELSE clk<='0';
8 ], P* B- u# p& q* q5 t1 C
END IF;
$ L* e2 A5 A; G) b5 ^# l% ~
cnt1:=cnt1+1;
" c- r9 i5 l+ ?2 Q) N
END IF;
- T5 [, r2 ?& B
END IF;
' T( h# C% |. [/ f2 I I
END PROCESS;
, e- R" f1 } Q. t5 o' w9 `
-------------------------------------------------------------------------------------
$ J( b& }: u9 k3 ]
process(clk) --generate 10hz clock signal
' M0 Q8 I8 [' O) A; X7 G- f
begin
Y% @8 E5 X! ~
if(clk'event and clk='1') then
# A# p/ c7 `! w. X4 }
clk10_count<=clk10_count+1;
4 m! B* `. Q4 z& @9 Q
if(clk10_count=16#3ff#) then
2 a$ [; I# d) u5 e
clk10<=not clk10;
) _: r+ A7 `3 c8 h
end if;
1 F1 b! y8 c. h
end if;
* E! p. K1 P& F B: E
end process;
2 c2 z S' _( s: f
-------------------------------------------------------------------------------------
" D8 { O: ~( u1 C
process(clk10)
. ]( Z! U& p: S ?6 d+ Q
begin
# v2 o6 g2 E6 ^7 E+ m$ s/ w2 d& V
if reset='0' then
. I; R5 a# a1 _2 j D/ O0 _9 e0 _( X0 H
se1<=0;
( K6 T8 F7 J3 s6 ~, \
se2<=0;
; k ] S% m8 s9 }$ L
se3<=0;
$ S! Z* [8 j+ U! b0 \
tone_index<=0;
4 s1 \% b5 n5 T( k5 n) P# l$ C; i+ S
elsif(clk10'event and clk10='1') then
( a! G) Y6 b6 o; d+ C1 w! d5 q
----------------------------------------------------------------------
9 h% ]/ X- p& O# D) C0 g4 Y
process(tone_index)
! G( J- `' f, |8 z7 T. t; Z
begin
9 L5 \ e2 _4 K4 a* S& h9 \* a4 b6 Y$ `
case tone_index is
7 o$ e Q- ^1 V" b5 ^
when 0=>tone<="11111111111"; --no output
! R* s! ~+ s/ I. T( z: Y
when 1=>tone<="01100000101"; --773--1
9 p/ c# a6 n* O+ G( y. {
when 2=>tone<="01110010000"; --912--2
* U" G3 K7 C0 b
when 3=>tone<="10000001100"; --1036--3
& E4 v* Q0 {3 g+ c& E* l
when 4=>tone<="10000111111"; --1087--4
! c: r! v+ X8 g! O1 p
when 5=>tone<="10010101101"; --1197--5
& p' W; v1 k" p" U8 Y4 o
when 6=>tone<="10100001010"; --1290--6
, `" w+ l0 \ t; a, ^3 h1 Y
when 7=>tone<="10101011100"; --1372--7
$ q0 Z3 L% c* u
when 8=>tone<="10110000010"; --1410--High 1
# f' K. y! ?5 o/ u+ Q3 ~ D; v3 G
when 9=>tone<="10111001000"; --1480--High 2
; P7 j& m- `# y: Y/ }8 N, o
when 10=>tone<="11000000110"; --1542--High 3
% ^; l/ x. a2 Q7 x5 {. a
when 12=>tone<="11000110000"; --1584--High 4
. m9 k, O+ h6 {* S0 A/ P/ }7 I& l
when 13=>tone<="11010000100"; --1668--High 5
1 P, k' W7 G) f- u+ `
when 16=>tone<="10001111111"; --1151--High #4
0 r% E# U9 l+ S
when 17=>tone<="10011110100"; --1766--High #5
8 ?' S$ J e# o& x) `
when 18=>tone<="10111100110"; --1510--High #2
7 h; j- d# }) Q0 G& J5 E( z
when others=>tone<="11111111111"; --others:no output
4 d3 `: {/ X% `8 [$ K* w
. `8 ] U; @2 A
end case;
5 H- s# h9 P2 h. }
end process;
; u7 C7 t5 e* [8 ]: t/ [* a) l
' D7 u$ |' ^- @& n' N
-------------------------------------------------------------------------------------
/ k% K) |7 i3 \, o( E0 M# m/ o+ h
process(clk) --control the frequence of the speaker
. U: S( J% E5 s( N* }5 O& d, M- {
begin
& \5 D% l ^5 C4 {( Z6 U& N8 |8 H# n
if(clk'event and clk='1') then
8 P: S' ]. P1 s2 _) k9 ^
if(tone_count=16#7ff#) then
" h9 R( ]% b0 E
tone_count<=tone;
S$ Z) E/ g/ {
if(tone<2047) then
% }7 y o D3 ^' ]
spk<=not spk;
1 o0 k. }2 T: a* f2 w" M/ _
end if;
5 S: X$ ]# E+ e5 N9 ~0 B
else
' K* p& r, j/ n. \% R5 z3 t3 v2 G
tone_count<=tone_count+1;
Q s2 ?- i) N6 H, \
end if;
) x8 t$ T1 K. O
end if;
% ] i* i) O7 q* s$ k4 J" l1 L6 S
end process;
: X' m2 {9 [9 U. W8 }- y
T' V! C8 `' I
end behave;
( f* L3 \- {4 d
6 L; |9 [" e: M8 t; h% g5 l
中 do 的773頻率 是如何算出來的??
- t9 l" j3 m0 t9 G4 p2 O7 V
那是用多少HZ去算的??
7 G: @9 L" {7 _" Y/ r
希望有公式給個解答
歡迎光臨 Chip123 科技應用創新平台 (http://www.chip123.com/)
Powered by Discuz! X3.2